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  1. great job showing the concept instead of just telling the youngsters formula's! love the physics vids. please do computer science soon khan… i would love to see some oop languages!

  2. Khan, pls pls relativity theory i cannot wait to see u explain it! and if ur time permits, pls explain some of the quantum mechanics concepts. dude, I love ur soul ^^ Salam

  3. This doesn't take into account the fact that jets on aircraft carriers take off into the wind, and the carriers themselves are also traveling forward with respect to the water.

  4. m8tate is correct, the jet needs an >airspeed< of 260km, so you should have subtacted the wind speed and ship speed from 260. Sill, its a fun problem.

  5. Thats not the runway. the runway is that slightly slanted one just to the right of that communications tower.

  6. I think the actual acceleration is a little higher by the end of the runway (which as mignik01 said is the ramp by the tower) due to the fact that I think the pilot often reaches take-off velocity before reaching the end of the ramp.
    I don't think the wind comment was very fair though (m8tate). Educational videos on YouTube can't be expected to successfully tutor people on mechanics whilst also involving friction, unless assumed to be constant.

  7. @JimNtexas Actually, @m8tate is wrong, the ship speed won't influence the speed needed for takeoff. And about the wing resistance, we can't calculate that unless you got the aerodinamical characteristics of a F/A 18 Hornet.

  8. @DekraDaFurry – While the airspeed needed to fly is what it is, in order the takeoff roll is definitely influenced by the wind speed over the deck (V0 in Sal's equation).

    It's highly unlikely that the F-18 could make a successful takeoff if the ship was stationary with no wind. The cat probably couldn't accelerate the jet to takeoff speed and it would fall into the drink.

    Try this thought experiment. Could the F-18 make a successful takeoff if the ship was going 100 knots in reverse?

  9. Don't you also have to consider the ships speed? It has an initial velocity of approx. 50kmh which is significant making the planes initial velocity of 50kmh if the ship is traveling forward in parallel with the runway.

  10. @JimNtexas Yes it could but only if there were a 200 knot wind traveling in the same direction as the ships travel(backward.).

  11. you sersly do not know any thing about these aircraft. you dont have to be me to know that you cant take off if theres planes in the way that strip with no plane is were they land and take off [email protected]#$

  12. @TheNalu7 shut up dumbfuck I hope you crash your fucking ass with your plane skills in afganistan fighting a pointless war. That is all…

  13. v sub i should be at least 15 m/s – this is after all taking off from an aircraft carrier which would be moving at a good speed not to mention turned into the wind.

  14. I was like no way, so it takes off in about 1 second so I YouTubed it and it did take off in about 1.5 seconds.

  15. We needed it bec-… Wait, 1 month old? What the heck. All we knew was how far the plane went, and how fast it needed to be going by the end of it. If the distance was 160 meters (twice as far) then the plane could accelerate at one half the speed (16.5 m/s^2).

  16. I recommend to use this formula x-x0 = 1/2(v0+v)t and then substitute 80m for x-x0 and 72m/s for v to get t = 2.22 s.Substitute the value of 't' and 'v' in this formula which is v = v0 + at to get a approx = 33m/s^2.It's that simple.

  17. Wait wait, I'm only 1:32 into the video, how are you able to use your mouse pointer like that in writing? You must have an amazing manual dexterity. ^5

  18. they take off and land on the same runway track. The place you said where they take off is plane holding area. just thought I would let you know 🙂

  19. Just want to point out none of these calculations account for drag, which is an extremely strong opposing force.

  20. Its not accurate as many already said, to takeoff and landing the carrier must be moving to reduce the airplane velocity…
    So, V0 is arround 50 km/h or 30 knots

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